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Re: Is the force of gravity 1/r^2 or 1/r????? - Astronomy ... 20 Apr 2011, 9:58 am
The ratio of g on the ground compared to > the acceleration g_h at height h is > g/g_h = (r+h)^2/r^2 > = 1 + 2rh/r^2 + h^2/r^2 > = 1 + 2h/r + (h/r)^2. > Under the assumption that h/r is "small", then > (h/r)^2 is "negligible". ...... Perhaps you should apply Occam's razor here – it works quite well in the majority of circumstances, and it says you should adopt the simplest model which explains all our experimental data. We know that the 1/r^2 law is obeyed to a very high ...
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